The simplest (total) of the atoms in the connection is the experimental formula of the connection. To determine the experimental formula of the given connection, the following steps are complied with; (I). Because the preparations in the percentage of elements are specified in the connection, we can assume that all are calculated from the 100 grams of the connection. Therefore, the percentage can be changed directly in the following grams. 74.97% Carbon (C) => 74.97 g of carbon (C) 8.39% hydrogen (H) => 8.39 g hydrogen (H) 16.64% Oxygen (O) => 16.64 g Oxygen (O) (II) in grams in grams in grams. Corresponding moon number; Remember it; 1 Carbon Moon contains 12 grams of atoms => 74.97 grams is molarbon => 74.97 grams of 6,2475 grams of carbon, 1 hydrogen atom contains 1 gram of atoms => 8.39 grams of mol Hydro = hydrogen =>> 8.39 grams are 8.39 mol hydrogen and 1 oxygen atom 1 mol containing 16 grams of atoms => 16.64 grams of moisture moisture for results. By sharing through the smallest (that is 1.04) | Carbon | Hydrogen | Oxygen | 6.2475 | 8.39 | 1.04 Dival of small people | = 6,007 | = 8.07 | = 1 (IV) Drive the results in (III) on the following unit | Carbon | Hydrogen | Oxygen | 6.2475 | 8.39 | 1.04 Dival of small people | = 6,007 | = 8.07 | = 1 meeting | 6 | 8 | 1 (V) is derived from Forulabia by experience using the numbers arising from the steps (IV) as the index, besides each of its corresponding elements as follows;