The simplest (total) of the atoms in the connection is the experimental formula of the connection.
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To determine the experimental formula of the given connection, the following steps are complied with; (I).
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Because the preparations in the percentage of elements are specified in the connection, we can assume that all are calculated from the 100 grams of the connection.
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Therefore, the percentage can be changed directly in the following grams.
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74.97% Carbon (C) => 74.97 g of carbon (C) 8.39% hydrogen (H) => 8.39 g hydrogen (H) 16.64% Oxygen (O) => 16.64 g Oxygen (O) (II) in grams in grams in grams.
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Corresponding moon number; Remember it; 1 Carbon Moon contains 12 grams of atoms => 74.97 grams is molarbon => 74.97 grams of 6,2475 grams of carbon, 1 hydrogen atom contains 1 gram of atoms => 8.39 grams of mol Hydro = hydrogen =>> 8.39 grams are 8.39 mol hydrogen and 1 oxygen atom 1 mol containing 16 grams of atoms => 16.64 grams of moisture moisture for results.
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By sharing through the smallest (that is 1.04) | Carbon | Hydrogen | Oxygen | 6.2475 | 8.39 | 1.04 Dival of small people | = 6,007 | = 8.07 | = 1 (IV) Drive the results in (III) on the following unit | Carbon | Hydrogen | Oxygen | 6.2475 | 8.39 | 1.04 Dival of small people | = 6,007 | = 8.07 | = 1 meeting | 6 | 8 | 1 (V) is derived from Forulabia by experience using the numbers arising from the steps (IV) as the index, besides each of its corresponding elements as follows;